Thursday, 23 July 2020

How to find the domain of a function

Finding the Domain of a Function

How to Help Your Kid If They're Struggling in Math - NJ Family
OK, so suppose we don't have the graph of a function to look at like in the last section...
Can we still find the domain and range?


Domains
:
Yes (as long as the algebra doesn't
get too hairy... and it won't for us.)


Ranges
:
Not really (you usually need the
picture -- unless it's something
really basic.)

So, we'll just be doing domains on these -- which is really where the action is anyway.


Asking for the
domain of a function
is the same as asking

"What are all the possible
x
guys
that I can stick into this thing?"



Sometimes, what you'll really be looking for is

"Is there anything I CAN'T stick in?"

Check it out:

Let's find the domain of f( x ) = 2 / ( x - 3 )
Do you see any
x

guys
that would cause a problem here?
What about x = 3 ?
f( 3 ) = 2 / ( 3 - 3 ) = 2 / 0 ... ouch!
 


So,
x
=
3
is a bad guy!  Everyone else is OK, though.

The domain is all real numbers except
3
.

What would the interval notation be?

When in doubt, graph it on a number line:

number line showing the domain is all numbers except 3
Do the interval notation in two pieces:

domain = ( -infinity , 3 ) U ( 3 , infinity )



YOUR TURN:

Find the domain of f( x ) = 5 / ( x + 7 )

Sometimes, you can't find the domain with a quick look.

Check it out:

Let's find the
domain
of
f( x ) = 1 / ( 3 - 2x )
Hmm...  It's not so obvious!

BUT, we are still looking for the same thing:

f( x ) = 1 / ( 3 - 2x ) The bad
x
that makes
the denominator
0
!
How do we find it?  Easy!

Set the denominator =
0
and solve!

3 - 2x = 0 ... subtract 3 from both sides ... -2x = -3 ... x = -3 / -2 = 3 / 2
The
domain
is
= ( -infinity , 3 / 2 ) U ( 3 / 2 , infinity )


TRY IT:

Find the domain of f( x ) = 6 / ( 5x + 3 ) *show work!!


How about this one?

f( x ) = square root( x + 5 )
Square roots -- what do we know about square roots?

                    square root( 16 ) = 4  ...  So,
16
is OK to put in.

                    square root( 0 ) = 0  ...  So,
0
is OK.

                    square root( 3.2 ) is about 1.788  ...  Yuck!  But,
3.2
is OK.

                    square root( -25 ) = ?  ...  Nope!  Can't do it!
  
                                                     

              
*We only want real numbers!


No negatives are OK!

square root( inside )
The
inside
of aradical
cannot be negative if we wantreal answers
only (no
i
guys).  So, the
inside
of aradical
has to be0 or a positive number
.

Set  inside is greater than or equal to 0  and solve it!
Now, let's find the domain of

f( x ) = square root( x + 5 ) ... x + 5 is greater than or equal to 0 ... x is greater than or equal to -5
So, the domain of f( x ) = square root( x + 5 ) is [ -5 , infinity ) .


TRY IT:

Find the domain of f( x ) = square root( 3 - x ) .
*Show work!!

Here's a messier one:

Let's find the domain of f( x ) = square root( 7 - 8x )

Set

 7 - 8x is greater than or equal to 0

 and solve!

7 - 8x is greater than or equal to 0 ... subtract 7 from both sides ... -8x is greater than or equal to -7 ... divide both sides by -8 ... x is less than or equal to 7 / 8
The domain is ( -infinity , 7 / 8 ] .


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